Science · Physics and chemistry · Topic 1 of 10
Light: Reflection, Refraction, Lenses and Defects of Vision
Think of it like…
A wari dindi stepping from the road onto the riverbank sand at Pandharpur
Picture a dindi of warkaris walking arm in arm, ten abreast, on the tar road towards the Chandrabhaga at Pandharpur. The road is hard, so they walk fast. Near the ghat the road gives way to soft sand, and the row meets the sand at a slant. The warkari at the left end steps into the sand first and slows down, while those still on the road keep their pace. For a few steps the left end is dragging and the right end is racing, so the whole row swings round and ends up walking more squarely into the sand. When they later climb back onto the road, the opposite happens and the row swings the other way. If they had met the sand head-on, everyone would slow together and nobody would turn.
Light does exactly this. Its speed is about 3 × 10⁸ m/s in air, less in water and still less in glass. When a beam enters a denser medium at a slant, the side that enters first slows first and the beam bends towards the normal; coming out it bends away from the normal. A beam hitting the boundary straight on passes without bending. A lens is just a patch of sand shaped cleverly: thicker in the middle (convex) so the central part of the row is held back longest and the row closes in to a point, or thinner in the middle (concave) so the row spreads out. Your eye is such a lens, and spectacles are a second lens added when the eye’s own lens cannot bring the row to a point on the retina.
| In everyday life | In the exam topic |
|---|---|
| Tar road where the row walks fast | Optically rarer medium (air), light travels faster |
| Soft sand where the row slows | Optically denser medium (water, glass), light travels slower |
| Row swinging when one end enters the sand first | Refraction: bending towards the normal on entering a denser medium |
| Row meeting the sand head-on and not turning | Light along the normal (angle of incidence 0°) passes undeviated |
| A sand patch thick in the middle that pulls the row to a point | Convex (converging) lens with a real focus |
| Adding a second sand patch so the row lands on the right spot | Spectacle lens correcting myopia (concave) or hypermetropia (convex) |
The concept
Reflection obeys two laws: the angle of incidence equals the angle of reflection, and the incident ray, reflected ray and normal lie in one plane. A plane mirror forms a virtual, erect, laterally inverted image as far behind the mirror as the object is in front. A concave mirror converges light; it gives a magnified virtual image when the object is inside the focus (shaving and dentist’s mirrors) and is used as the reflector in torches and headlights with the bulb at the focus. A convex mirror always gives a small, erect, virtual image but covers a wide field of view, which is why it is the rear-view mirror of every ST bus and the mirror at blind turns on ghat roads. The mirror formula (NCERT sign convention) is 1/v + 1/u = 1/f, with f = R/2.
Refraction happens because light changes speed between media. The refractive index n = c / v (speed in vacuum ÷ speed in the medium); for glass n ≈ 1.5, so light moves at 3 × 10⁸ ÷ 1.5 = 2 × 10⁸ m/s in it. Snell’s law: sin i / sin r = constant. When light goes from a denser to a rarer medium at more than the critical angle, none of it escapes: this is total internal reflection, behind optical fibres, the sparkle of diamond (n ≈ 2.42, critical angle about 24°) and the desert or highway mirage. Atmospheric refraction makes stars twinkle (planets, being nearer discs, generally do not) and lets us see the Sun about two minutes before actual sunrise and after actual sunset. A prism splits white light into VIBGYOR (dispersion) because each colour has a slightly different speed in glass; violet deviates most, red least. A rainbow combines dispersion, refraction and internal reflection in raindrops and is always seen with the Sun behind you. The sky is blue because tiny air molecules scatter short (blue) wavelengths much more than long (red) ones; red light is scattered least, so it travels farthest, which is why danger signals and the setting Sun are red.
Lenses. A convex lens converges light and a concave lens diverges it. The lens formula is 1/v − 1/u = 1/f, and power P = 1/f with f in metres, measured in dioptres (D). Convex lenses have positive power, concave negative. For thin lenses in contact powers simply add: P = P₁ + P₂. This makes optometry numericals quick: an optician’s prescription of −2.0 D means a concave lens of focal length 50 cm.
The eye and its defects. The eye lens focuses images on the retina; the ciliary muscles change its focal length (accommodation). A normal adult eye sees clearly from the near point of 25 cm to infinity. Myopia (short-sightedness): distant objects are blurred because the image forms in front of the retina (eyeball too long or lens too curved); corrected with a concave lens. Hypermetropia (long-sightedness): near objects are blurred, image behind the retina (eyeball too short); corrected with a convex lens. Presbyopia: age weakens the ciliary muscles, so near vision fails; often both defects coexist and a bifocal lens is used. Astigmatism needs a cylindrical lens. Cataract is clouding of the eye lens, treated by surgery. Rods respond to dim light and cones to colour; night blindness is linked to vitamin A deficiency.
Key points & formulas
- Refractive index n = c / v; light in glass (n = 1.5) travels at 2 × 10⁸ m/s
- Power P = 1/f (f in metres); unit dioptre (D); convex +, concave −; P = P₁ + P₂ for lenses in contact
- Mirror formula 1/v + 1/u = 1/f; lens formula 1/v − 1/u = 1/f; f = R/2 for mirrors
- Convex mirror: rear-view mirror (wide field, erect diminished image). Concave mirror: headlights, shaving, dentist
- Total internal reflection: optical fibre, diamond sparkle, mirage (denser → rarer, angle > critical angle)
- Dispersion: violet deviates most, red least. Scattering: blue sky; red sunset and red danger signals
- Atmospheric refraction: twinkling stars, Sun visible about 2 minutes before sunrise and after sunset
- Near point of normal eye 25 cm, far point infinity; accommodation by ciliary muscles
- Myopia → concave lens; hypermetropia → convex lens; presbyopia → bifocal; astigmatism → cylindrical
- Cataract: opaque eye lens, corrected by surgery; rods = dim light, cones = colour
Worked example
A farmer from Satara can read a newspaper clearly only when he holds it at 1 m. His neighbour cannot see objects beyond 2 m clearly. Name each defect and find the power of the lens each needs (normal near point 25 cm).
Show solution
- Farmer: near objects blurred, so this is hypermetropia. The lens must take an object at u = −25 cm and form a virtual image at his near point, v = −100 cm.
- Lens formula: 1/f = 1/v − 1/u = 1/(−100) − 1/(−25) = −0.01 + 0.04 = 0.03 per cm, so f ≈ +33.3 cm.
- P = 100 / f (cm) = 100 × 0.03 = +3 D, a convex lens.
- Neighbour: distant objects blurred, so this is myopia. The lens must make objects at infinity appear to come from his far point, so f = −2 m.
- P = 1 / (−2) = −0.5 D, a concave lens.
Answer: Farmer: hypermetropia, convex lens of +3 D. Neighbour: myopia, concave lens of −0.5 D.
Exam shortcut
Sign tells shape: “plus is convex, minus is concave.” And the defect name tells you what still works: myopia = my near vision is fine (needs concave); hypermetropia = horizon is fine, near is blurred (needs convex).
Common traps
- Myopia is corrected by a concave lens, not convex. Candidates often reverse this because “short-sighted” sounds like it needs magnification.
- Light bends towards the normal when entering a denser medium and away from it when leaving; total internal reflection happens only from denser to rarer.
- Red light is scattered the least (that is why it is used for danger signals); blue is scattered more. Do not mix up “scattered most” with “visible farthest”.
- Focal length must be in metres for power in dioptres: f = 25 cm gives P = 1/0.25 = +4 D, not 1/25.
- A rainbow is seen in the direction opposite the Sun, so morning rainbows appear in the west.
Practice · tap an option to check
Q1. A student can read the blackboard notes in his notebook easily but finds the blackboard itself blurred from the last bench. Which defect does he have, and how is it corrected?
Answer: A. Far objects blurred and near objects clear is myopia: the image forms in front of the retina, so a diverging (concave) lens pushes it back. A convex lens would make it worse.
Q2. Two thin lenses of power +4 D and −2.5 D are placed in contact. The combination behaves as:
Answer: C. P = +4 + (−2.5) = +1.5 D. Positive power means converging, and f = 1/1.5 m ≈ 0.667 m = 66.7 cm. 25 cm is the focal length of the +4 D lens alone.
Q3. Consider the following statements:
1. A rainbow is seen in the same direction as the Sun.
2. Stars twinkle because of atmospheric refraction, while planets generally do not twinkle.
Which of the statements given above is/are correct?
Answer: B. A rainbow is always seen with the Sun behind the observer, so statement 1 is wrong. Stars are point sources whose light is bent by shifting air layers; planets are nearer and appear as tiny discs, so the flicker averages out.
Q4. Match List I with List II:
List I: a. Rear-view mirror of an ST bus b. Dentist’s mirror c. Correcting astigmatism d. Correcting presbyopia with both defects
List II: 1. Concave mirror 2. Convex mirror 3. Bifocal lens 4. Cylindrical lens
Answer: D. A convex mirror gives a wide field of view (a-2); a concave mirror held close magnifies the tooth (b-1); astigmatism needs a cylindrical lens (c-4); presbyopia with both near and far problems needs a bifocal (d-3).